SOLUTION: Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the equation of the quadratic function. (h, k) = (−3, −1), (x, y) = (−5, 3) * can some

Algebra.Com
Question 1136384: Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the equation of the quadratic function.
(h, k) = (−3, −1), (x, y) = (−5, 3)
* can someone help? So far I’ve gotten 1/4(x+3)^2-1, but it is incorrect. I’ve plugged the given numbers into their respective places in the formula, y=a(x-h)^2+k, but am lost where I’m going wrong. Thank you.

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

(, ) = (, ), (,) = (, )
...given ,.,; plug it all in and calculate





your equation is:



RELATED QUESTIONS

Use the vertex (h, k) (-4,-1) and a point on the graph (x, y) (-6,3) to find the... (answered by ikleyn)
Use the vertex (h, k) and a point on the graph (x, y) to find the general form of (answered by josgarithmetic,MathTherapy)
Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the... (answered by josgarithmetic)
Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the... (answered by josgarithmetic)
Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the... (answered by josgarithmetic)
Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the... (answered by josgarithmetic)
Using the vertex (h,k) and a point on the graph (x,y), how do I find the general equation (answered by MathLover1)
Show that the quadratic function {{{y=ax^2+bx+c}}} can be written in the form... (answered by fcabanski)
Use the vertex (0, 3)and a point on the graph (2, 7) to find the general form of the... (answered by josgarithmetic)