SOLUTION: Find 3 consecutive odd integers if the difference of the squares of the least and greatest is 120.

Question 1134352: Find 3 consecutive odd integers if the difference of the squares of the least and greatest is 120.
Found 3 solutions by Alan3354, ankor@dixie-net.com, MathLover1:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find 3 consecutive odd integers if the difference of the squares of the least and greatest is 120.
=================
(n+4)^2 - n^2 = 120
8n + 16 = 120
n = 13
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Find 3 consecutive odd integers
a, (a+2), (a+4)
if the difference of the squares of the least and greatest is 120.
(a+4)^2 - a^2 = 120
FOIL (a+4)(a+4)
a^2 + 8a + 16 - a^2 = 120
8a = 120 - 16
a = 104/8
a = 13 is the 1st odd integer
then, obviously
15 and 17 are the next two
:
:
Check on your calc: 17^2 - 13^2 =
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

Find consecutive odd integers if the difference of the squares of the least and greatest is .

To determine these integers, we start by letting the first odd integer be . Then we can represent the three consecutive odd integers as ,, and .
the squares of the least and greatest is: and
if the of the squares of the least and greatest is , we have

then , and
your odd integers are: , , and

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