SOLUTION: The solubility equilibrium constant for the dissolution of copper (I) chloride into copper ions and chlorine ion is Ksp = [Cu+][Cl-]. If the solubility constant is Ksp = 1.7 � 1

Question 1130327: The solubility equilibrium constant for the dissolution of copper (I) chloride into copper ions and chlorine ion is Ksp = [Cu+][Cl-].
If the solubility constant is Ksp = 1.7 � 10-7, and the concentration of chlorine (Cl-) is 0.2 mol/L greater that the concentration of copper (Cu+), what is the concentration of copper ions in solution? Round your answer to 2 significant figures.
The concentration of copper ions in solution is
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
.
Go directly to some Chemistry site helping students, and post your question/problem there.

Good luck !

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Let x be [] and therefore x+0.2 is the [] concentration.

,

Solve for x.
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