SOLUTION: Use the model for the period of a pendulum, T, such that T = 2π sqrt (L/ g), where the length of the pendulum is L and the acceleration due to gravity is g. If the acce

Algebra.Com
Question 1124490: Use the model for the period of a pendulum, T, such that T = 2π sqrt (L/ g),
where the length of the pendulum is L and the acceleration due to gravity is g.
If the acceleration due to gravity is 9.8 m/s2 and the period equals 5 s, find the length to the nearest cm
(100 cm = 1 m).

*For this, I am completely lost as to both how the equation should be set up and the steps needed to solve the problem. If someone could help, it would be greatly appreciated!*

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
T =   ====>  square both sides  ====>


 = 


 = L


L =  =  = 6.21 meters = 621 centimeters = 621 cm.


RELATED QUESTIONS

Use the model for the period of a pendulum, T, such that T = 2π sqrt(L/g), where... (answered by MathLover1)
Use the model for the period of a pendulum, T, such that T = 2π sqrt(L/g) where... (answered by rothauserc)
Derivation of T ∝ √l Derivation of T = 2π√(l/g) T = Time... (answered by fractalier)
The time T (in seconds) required for a pendulum to make one complete swing back and forth (answered by ikleyn)
the time T (in seconds ) taken for one complete swing of a pendulum is given by T=2pi... (answered by ikleyn)
The formula for the period of a pendulum is t=2[pi]sqrt(L/G) where t is the period in... (answered by nyc_function)
The period of a pendulum is equal to 2π√(l/g), where l is the length of the... (answered by ikleyn)
Simple Pendulum Gravity is responsible for an object falling toward Earth. The farther... (answered by stanbon)
the length of a pendulum is directly proportional to the square of the time it takes for... (answered by stanbon)