SOLUTION: What is an equation in standard form of the parabola that has the same shape as the graph of f(x)=−3x^2, but with vertex at (−16,−14).
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Question 1120590: What is an equation in standard form of the parabola that has the same shape as the graph of f(x)=−3x^2, but with vertex at (−16,−14).
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Put the given function in vertex form: \ =\ a(x\ -\ h)^2\ +\ k)
, to wit:
\ =\ -3(x\ -\ 0)^2\ +\ 0)
Now insert the coordinates of the new vertex:
\ =\ -3\(x\ -\ (-16)\)^2\ +\ (-14))
and simplify:
\ =\ -3(x\ +\ 16)^2\ -\ 14)
John
My calculator said it, I believe it, that settles it
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