.
f(x) = 2x^2 - 8x + 11 = 2*(x^2 - 4x) + 11 = 2*(x^2 - 2*2*x + 2^2) - 2*2^2 + 11 =
= 2*(x-2)^2 + 3.
The vertex is (2,3).
The y-intercept is 11. It is the value of f(x) at x= 0.
There is no x-intercept: the plot of the function does not intersect x-axis.
It is ALWAYS ABOVE the x-axis.
Plot y =
Done.
--------------
To see many other similar problems solved by the "completing the square" method and to learn the subject, look into the lesson
- HOW TO complete the square - Learning by examples
in this site.