SOLUTION: Write a quadratic equation in standard form with the roots. a) 3+√2 and 3-√2, passes through point (3,1) b) -1+2√3 and -1-2√3, passes through point (-1,4)

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Question 1118785: Write a quadratic equation in standard form with the roots.
a) 3+√2 and 3-√2, passes through point (3,1)
b) -1+2√3 and -1-2√3, passes through point (-1,4)

Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Here is help for (a) only.






Solve the formula for a.


Substitute the given point.



Substitute for the now found value of a in the factored form.


From that, continue to simplify to get the 'standard' form you want.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


The purely algebraic method used by the other tutor is fine; however, with the roots 3+sqrt(2) and 3-sqrt(2), the algebra gets a bit messy.

There is a much easier path to the answers.

In the quadratic equation



the sum of the roots is -b/a and the product of the roots is c/a. Then we can write the equation as



In your first example, the sum of the roots is 6 and the product is 9-2=7. So an equation of the parabola is



Then you can find the value of a by substituting the (x,y) values of the given point on the parabola:




And the whole equation is



Then of course use the same method on your second example, where the sum of the roots is -2 and their product is 1-12 = -11.

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