SOLUTION: Amy, Chau, and Juan have a total of 90 in their wallets. Amy has 5 more than Chau. Juan has 3 times what Amy has. How much do they have in their wallets?

Question 1117671: Amy, Chau, and Juan have a total of 90
in their wallets. Amy has 5
more than Chau. Juan has 3
times what Amy has. How much do they have in their wallets?

Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
.

Amy + Chau + Juan = 90 A + C + J = 90 || || (C+5) + C + 3*(C+5) = 90 3C + 5 + 15 = 90 5C + 20 = 90 ====> 5C = 90 - 20 = 70 ====> C = = 14. Answer. Chau has 14; Amy has 14+5 = 19; Juan has 3*19 = 57. Check 14 + 19 + 57 = 90. ! Correct !

Solved.

Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

Amy, Chau, and Juan have a total of :
....eq.1

if Amy has than Chau, we have
=>...eq.2
if Juan has what Amy has, we have
...eq.3

....eq.1 substitute values rom eq.2 and eq.3

=>=>
=>=>

How much do they have in their wallets?
has
has
has

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