SOLUTION: Write a formula for a function with a graph that has three xx-intercepts, (-3, 0), (1, 0), and (4, 0). The equation for a cubic graph like this was given to me as y=a(x-h)^3+k

Question 1117218: Write a formula for a function with a graph that has three xx-intercepts, (-3, 0), (1, 0), and (4, 0).
The equation for a cubic graph like this was given to me as y=a(x-h)^3+k
a=stretch factor
h=move graph left/right
k=move graph up/down
I don't know how to find the equation with those three x intercepts.
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
There is some mix-up in your understanding and in your input.

What they want from you is to find (to write an equation for) the function which has zeroes at assigned points x= -3, x= 1 and x= 4.

The simplest function which has the assigned zeroes (roots), is the third degree polynomial

f(x) = (x-(-3))*(x-1)*(x-4).

It is constructed as the product of linear binomials, associated with the given zeroes.

In more simple form it is

f(x) = (x+3)*(x-1)*(x-4).

You can further to make distributive multiplication and open parentheses, if you want or if you need.

Solved.

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