SOLUTION: The coin is in the shape of a circle of radius 3 cm with a square of sides x cm removed from its centre. The area of each face of the coin is 7pi cm^2.
i) form an equation in x a
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Question 1113073: The coin is in the shape of a circle of radius 3 cm with a square of sides x cm removed from its centre. The area of each face of the coin is 7pi cm^2.
i) form an equation in x and show that it reduces to 2pi-x^2=0.
ii) solve the equation 2pi-x^2=0.
iii) find the perimeter of the square
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The coin is in the shape of a circle of radius 3 cm with a square of sides x cm removed from its centre.
The area of each face of the coin is 7pi cm^2.
i) form an equation in x and show that it reduces to 2pi-x^2=0.
=
=
= 0
:
ii) solve the equation 2pi-x^2=0.
x =
:
iii) find the perimeter of the square
p =
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