SOLUTION: I am graphing a parabola and I have all of my points done but I'm having a problem getting the x & y vertex's....the equation is 3x�-x-1=0 ...I have 1.5 for x but I'm told this is

Question 111223: I am graphing a parabola and I have all of my points done but I'm having a problem getting the x & y vertex's....the equation is 3x�-x-1=0 ...I have 1.5 for x but I'm told this is wrong and I have no idea how to solve it for the y vertex. Please help!
Thanks so much!
B. Cook
Found 2 solutions by solver91311, checkley71:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
In general, for , vertex at (h, k), , and .
:
So, for your particular problem, b = -1 and a = 3. That makes , and
:

:
Putting the vertex squarely on the point (1/6,-39/36)
:
Send me a note if there is any part of that you don't understand.
:
John
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
Y=3X^2-X-1
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 3x^2 -x -1).
x=-b/2a
x=-(-1/2*3)
x=-(-1/6)
x=1/6 answer for the x coordinate of the vertex.
y=3(1/6)^2-1/6-1
y=3(1/36)-1/6-1
y=3/36-1/6-1
y=1/12-1/6-1
y=(1-2-12)/12
y=-13/12 the y coordinate of the vertex.
vertex=(1/6,-13/12)
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