SOLUTION: Find the discriminant and give the number of real solutions. 2x^2-x+5=0

Question 1110461: Find the discriminant and give the number of real solutions.
2x^2-x+5=0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the discriminant and give the number of real solutions.
2x^2-x+5=0
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good idea.
It's in the form:
ax^2 + bx + c = 0
a = 2
b = -1
c = 5
---
Disc = b^2 - 4ac
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If Disc < 0 --> 2 complex solutions.
If Disc = 0 --> 2 real equal solutions.
If Disc > 0 --> 2 different real solutions.
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There are ALWAYS 2 solutions.

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