.
The condition says: substitute x= -4 and y= -3 into the given system; then solve it for "p" and "q".
When you substitute, you will get
-4p - 3q = -26,
-4q - (-3)p = 7,
or, equivalently,
4p + 3q = 26, (1)
3p - 4q = 7. (2)
To solve it, multiply eq(1) by 3 (both sides) and nultiply eq(2) by 4 (both sides). You will get
12p + 9q = 78,
12p - 16q = 28.
------------------------Now subtract eq(4) from eq(3) (both sides). You will get
25q = 78 - 28 = 50 ====> q = = 2.
Then from (2) 3p = 7 + 4q = 7 + 4*2 = 15 ====> p = = 5.
Answer. p = 5, q = 2.