SOLUTION: Write the equation of the parabola in both vertex and standard form whose vertex is (-1,-4) and passes through (0,-5). My work was: {{{ y=a(x-h)^2+k }}} Vertex Form {{{ y

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Question 1098342: Write the equation of the parabola in both vertex and standard form whose vertex is (-1,-4) and passes through (0,-5).

My work was:

Vertex Form
Substituted (-1,-4) into (h,k) values
Substituted (0,-5) into (x,y) values
Solve for a

Giving a vertex form of =
Finding standard form using
wasn't sure if I was supposed to distribute the negative here, I didn't

and I got standard form of =
I'm unsure about the procedure, especially with the negative for standard form, but I might be overthinking it, any advice would be appreciated!

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Write the equation of the parabola in both vertex and standard form whose vertex is (-1,-4) and passes through (0,-5).

My work was: 

 
 Vertex Form

 Substituted (-1,-4) into (h,k) values

 Substituted (0,-5) into (x,y) values

 Solve for a 




Giving a vertex form of = 


Finding standard form using    

 wasn't sure if I was supposed to distribute the negative here, I didn't     
                              <<<---=== until this line and including this line everything is correct.      


                 <<<---===  This line is WRONG.  It should be  y = -x^2 -2x - 1 - 4 = -x^2 - 2x - 5.

and I got standard form of =

---------------------
Your final expression should be   y = -x^2 - 2x - 5.



Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!





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