SOLUTION: Let f(x) = x^2 + 4x - 31. For what value of a is there exactly one real value of x such that f(x) = a?
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Question 1096609
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Let f(x) = x^2 + 4x - 31. For what value of a is there exactly one real value of x such that f(x) = a?
Answer by
ikleyn(52780)
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HINT: this value of x and this value of "a" form the vertex of the given parabola.
=
=
. So, this value of "a" is a = -35, and this value of "x" is x = -2.
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