SOLUTION: I am supposed to find k in the following quadratic equation: (k+3)x^2 + 2kx + 4 = 0. I have tried using the quadratic formula and unless I'm doing something wrong I don't com

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Question 109585: I am supposed to find k in the following quadratic equation:
(k+3)x^2 + 2kx + 4 = 0.
I have tried using the quadratic formula and unless I'm doing something wrong I don't come up with k. I have tried using the discriminant to find k with no success. I must be missing something easy.
Thanks for your help, Don

Found 2 solutions by jim_thompson5910, edjones:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Are you trying to find a k that yields one real solution? If you are, then the discriminant must equal zero. So

which means







Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for k:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=4, b=-16, and c=-48




Negate -16 to get 16




Square -16 to get 256 (note: remember when you square -16, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 4 to get 8


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or





So if k=-2 or k=6, then it will give us one solution for

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
(k+3)x^2 + 2kx + 4 = 0.
kx^2+3x^2+2kx+4=0
kx^2+2kx=-3x^2-4
k(x^2+2x)=-3x^2-4
k=(-3x^2-4)/(x^2+2x)
Ed

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