SOLUTION: Find the (x,y) coordinate of the maximum or minimum value
of the following quadratic equation:-1/6x^2-1/3x+8=y
Algebra.Com
Question 1094691: Find the (x,y) coordinate of the maximum or minimum value
of the following quadratic equation:-1/6x^2-1/3x+8=y
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The x-value of the vertex
( maximum or minimum ) is at:
-----------------
plug this value back into equation
---------------------
The vertex is at ( -1, 49/6 )
--------------------------
Here's the plot:
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