SOLUTION: Determine the number of real roots of the equation 3x-2=4/(2-x)

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Question 1093399: Determine the number of real roots of the equation 3x-2=4/(2-x)
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

A value which would NOT be a root would be x=2, because the right side expression would be undefined for this value. It might or might not come up during the solution process.








discriminant, ----------Negative value.
NO real roots.









-
(fixed)

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Determine the number of real roots of the equation 3x-2=4/(2-x)
~~~~~~~~~~~~~~~~~

 =   ====>

(3x-2)*(2-x) = 4,

6x -3x^2 - 4 +2x = 4,

-3x^2 +8x - 8 = 0,  ====>

3x^2 -8x + 8 = 0,

discriminant  d =  = 64 - 96 = -32.


Since the discriminant is NEGATIVE, there are no real solutions.


Answer.  The number of real roots of the equation 3x-2=4/(2-x) equal to 0 (zero, ZERO).


And the plot below  ILLUSTRATES  it.




Plot y = 3x-2 (red) and y = 4/(2-x) (green)


The solution by @josgarithmetic was  W R O N G.  Simply ignore it.



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