SOLUTION: An object is launched into the air from a ledge 6 feet off the ground at initial vertical velocity of 96 feet per second. Its height H, in feet, at t second is given by the equatio

Question 1087720: An object is launched into the air from a ledge 6 feet off the ground at initial vertical velocity of 96 feet per second. Its height H, in feet, at t second is given by the equation H = 16t^2+96t+16. Find all the times t that the object is at a height of 160 feet off the ground.
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52780) (Show Source): You can put this solution on YOUR website!
.
I just answered to this post at
https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1087634.html

https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1087634.html

saying that your post contains at least TWO errors (one of which is FATAL).

I asked you to double check your input and to fix the errors.

In response, you did NOTHING, submitting the post with no change and with the same errors.

So, AGAIN:

Carefully check your post.

Read and re-read it until you find the errors.

Then fix them.

Then re-post.

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The equation should be:

( I noted you said at the
object was ft off the ground,
it should be ft. )
----------------------------------

The object is at a height of 160 ft
only once, at t = 3 sec
--------------------------------
check:
here's the plot:

My answer looks about right
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