SOLUTION: The quadratic x^2+1300x+1300 can be written in the form (x+b)^2+c, where b and c are constants. What is c/b?

Question 1085954: The quadratic x^2+1300x+1300 can be written in the form (x+b)^2+c, where b and c are constants. What is c/b?
Found 2 solutions by rapture, MathLover1:
Answer by rapture(86) (Show Source): You can put this solution on YOUR website!
We must complete the square as step one.

(1300/2)^2 = 422,500. Add to both sides.

x^2 + 1300x + 422,500 = -1300 + 422,500

x^2 + 1300x + 422,500 = 421,200

(x + 650)(x + 650) = 421,200

(x + 650)^2 - 421,200 = 0

c = -421,2000

b = 650

So, c/b = -421,200/650

c/b = -648

Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

can be written in the form , where and are constants
....complete square

....since ,=>=>

-> and

and

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