SOLUTION: 1. Find the area in simplified form for a rectangle with a length of \sqrt{24} and a width of \sqrt{18}
2. What is the area for a rectangle with a base of \sqrt{3}x^3y^2 and len
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Question 1085868: 1. Find the area in simplified form for a rectangle with a length of \sqrt{24} and a width of \sqrt{18}
2. What is the area for a rectangle with a base of \sqrt{3}x^3y^2 and length \sqrt{6}xy^3.
Found 2 solutions by rapture, ikleyn:
Answer by rapture(86) (Show Source): You can put this solution on YOUR website!
A = L•W
Part 1
A = sqrt{24}•sqrt{18}
A = sqrt{24 • 18}
A = sqrt{432}
A = 20.7846096908
A = 20.8
Part 2
A = [sqrt{3}•x^3•y^2][sqrt{6}•x•y^3]
A = sqrt{3•6}•x^4•y^5
A = sqrt{18}•x^4•y^5
A = sqrt{9}•sqrt{2}•x^4•y^5
A = 3•sqrt{2}•x^4•y^5
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Part 1.
= . = = = = 20.7846.
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