SOLUTION: How can I solve (x+3)(x+4)=0 and 2x(x-3)=15????

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Question 1083942: How can I solve (x+3)(x+4)=0 and 2x(x-3)=15????

Found 2 solutions by Alan3354, rothauserc:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
duplicate
Answer by rothauserc(4718)   (Show Source): You can put this solution on YOUR website!
the standard form of a quadratic equation is
:
ax^2 +bx +c = 0, where a is not equal to 0
:
do you have to solve each equation for its x-axis intercepts or the intersection point of both equations?
:

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