SOLUTION: completing the square -1/2x²+4x-6=0

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Question 108379: completing the square
-1/2x²+4x-6=0

Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
-1/2x²+4x-6=0
Multiply thru by -2 to get:
x^2-8x+12 = 0
Complete the square on the x terms and keep the equation balanced.
----------
x^2-8x = -12
x^2-8x+16 = -12+16
(x-4)^2 = 4
--------------
Take the square root of both sides to get:
x-4 = 2 or x-4 = -2
x = 6 or x = 2
====================
Cheers,
Stan H.

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!

Let's multiply both sides by (-2) to get rid of the fraction.

Simplify.
We want to find a constant, a, such that,
Expand the perfect square equation.
Compare coefficients of that equation with your equation,


If a=-4, the .
In order get get 16 on the left hand side of the equation, that is, in order to complete the square, you need to add 4 to the left hand side.
Whatever you do to one side of the equation, you must do to the other side.

Add 4 to both sides.
Complete the square.
and




Check your answers.








Both answers lead to true statements.
Good answers.

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