SOLUTION: The function f(x)=2x^2+12x+32 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?

Question 1082300: The function f(x)=2x^2+12x+32 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?

Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
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This post HAS NO ANY SENSE.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The function f(x)=2x^2+12x+32 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?
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The function is in x, not t.
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If it's f(t):
f(t) = 2t^2 + 12t + 32
it will never "hit the ground," that is, f(t) will never = zero (0).
f(0) = 32, and it increases with t.
It's a real rocket (tho not a good function), not a projectile.

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