SOLUTION: 1.Sketch the graph of y=-x2-2x+3
2.Sketch the graph of y=-x2+2x-2
3.Find the equation for the linear function that is parallel to f(x)=3/2x-3 through (4,-1)
4.Find the equation
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Question 1079056: 1.Sketch the graph of y=-x2-2x+3
2.Sketch the graph of y=-x2+2x-2
3.Find the equation for the linear function that is parallel to f(x)=3/2x-3 through (4,-1)
4.Find the equation of the line that is perpendicular to the equation f(x)=2.5x-0.5 through (-4,2)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x^2-2x+3
-x^2+2x-2
parallel lines have the same slope
point slope formula where y-y1=m(x-x1), m slope, (x1,y1) a point. Watch the signs.
y+1=(3/2)(x-4) and y=(3/2)x-7
Perpendicular lines have a negative reciprocal slope
slope of the given line is 5/2, so line perpendicular has a slope of -2/5
y-2=(-2/5)(x+4)
y=(-2/5)x+(2/5)
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