SOLUTION: The length of a square is increased by a 5th so that its new area is 44cm^2 more than the original value. Find the difference in perimeter of two shapes.
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Question 1078906: The length of a square is increased by a 5th so that its new area is 44cm^2 more than the original value. Find the difference in perimeter of two shapes.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The length of a square is increased by a 5th so that its new area is 44cm^2 more than the original value. Find the difference in perimeter of two shapes.
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10 cm square --> area of 100 sq cm
12 cm square --> area of 144 sq cm
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4*(12-10) = 8 cm difference in perimeter
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