SOLUTION: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Determine t

Algebra.Com
Question 1075030: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Determine the maxima or minima.

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
L=W+2
A=(W+2)(W)=W^2+2W=8
W^2+2W-8=0
(W+4)(W-2)=0
W=2 only positive root.
L=4
Minimum at w=-1, function= -9

RELATED QUESTIONS

The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 (answered by Fombitz)
The length of a rectangle is 8 feet longer than its width, which has the same dimension... (answered by solver91311)
The width of a rectangle is 7 feet longer than the length. If the area is 330 square... (answered by london maths tutor)
The length of a rectangle is 3 feet longer than twice the width. If the area is 54 square (answered by TimothyLamb)
The length of a rectangle is 8 feet more than the width. If the area of the rectangle is... (answered by TimothyLamb)
The area of a rectangle in square feet is x^2+13x+36. How much longer is the length... (answered by josmiceli,ikleyn)
The area of a rectangle is 80 square feet. The length is 2 feet longer than the width.... (answered by oberobic)
The area of a rectangle is 36 square feet. Find the length and the width of the rectangle (answered by ikleyn)
The length of a rectangle is 2 feet more than the width. The area of the rectangle is 2... (answered by Alan3354,Theo,ikleyn)