SOLUTION: Lorna wants to enclose a rectangular area next to the river. She only has 400 ft. of fence and she wants to enclose an area of 1500 ft2 , set the rectangular area dimensions

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Question 1074413: Lorna wants to enclose a rectangular area next to the river. She only has 400 ft. of
fence and she wants to enclose an area of 1500 ft2
, set the rectangular area
dimensions

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
If x is one dimension and y is the other, and if y is the side opposite the river bank, then:


Solve this system.

If substituting for y,





.
.

Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.
Let x be the dimension along the river and y that perpendicular to the river.

Then

x + 2y = 400,   (1)
xy = 1500.      (2)


From (1), x = 400 - 2y. Substitute it into (2). You will get

(400-2y)*y = 1500.

2y^2 -400y + 1500 = 0,

y^2 - 200y + 750 = 0,

 =  =  = .

There are 2 solutions:  1) y = 196.18 ft;  then  x = 400 - 2*196.18 =  15.29 ft.

                        2) y =   3.82 ft;  then  x = 400 - 2*3.82   = 392.36 ft.

Check.  1)  196.18*7.64 = 1499 ft^2  (close !);   2) 3.82*392.36 = 1500 ft^2.

Answer. 1) x = 15.29 ft, y = 196.18;  2) x = 392.36, y = 3.82 ft.


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