SOLUTION: If p and q are the roots of x^2+PX+q=0. Find p and q?

Algebra.Com
Question 1073525: If p and q are the roots of x^2+PX+q=0. Find p and q?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Starting with , and assigning roots as p and q, and working with the roots from use of quadratic formula,




If p and q are to be roots for then this system should be possible:




The second of these means p=1; and substituting into the first of these gives a way to solve for q.
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
1.  Writing by "josgarithmetic" is   W R O N G   F R O M   T H E   B E G I N N I N G   T O   T H E   E N D.


2.  Your writing is also wrong. 

   The correct writing is this:


   If p and q are the roots of x^2+px+q=0, find p and q.

Do you see the difference ?


Hey, you want to get the help from tutors.

You want tutors work for you.


Do you feel the duty from your side to write the post correctly ?


Do you understand what I am talking about ?



RELATED QUESTIONS

If p and q are the roots of the equation 2x^2-x-4=0. Find the equation whose roots are... (answered by Fombitz,youngguru23)
If p and q are the roots of the equation {{{2x^2-x-4=0}}} Find the equation whose... (answered by ikleyn)
If p and q are roots of quadratic equation x2-px+q=0 , what is value of p and... (answered by richard1234)
All the roots of x^2 + px + q = 0 are real, where p and q are real numbers. Prove that... (answered by ikleyn)
find the value of x if p+7=0,q-12=0 and... (answered by richard1234)
If 2 + √3 is one root of xpower2 + px + q = 0 Then p and q... (answered by josgarithmetic,MathTherapy)
if the ratio of the roots of the equation x^3+5x^2+px+q=0 are w, 2w, and w+3, find the... (answered by greenestamps)
The roots of the equation x^2+px+1=0 are a and b and the roots of the equation x^2-9x+q=0 (answered by robertb)
find the values of p and q respectively if (x-2) and (x+1) are both factors of... (answered by josgarithmetic)