SOLUTION: It takes Kenny 1 hour longer than Dennis to shuck a sack of oysters. IF together they shuck a sack of oysters in 45 minutes, then how long would it take each one working alone?

Question 1069135: It takes Kenny 1 hour longer than Dennis to shuck a sack of oysters. IF together they shuck a sack of oysters in 45 minutes, then how long would it take each one working alone?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
It takes Kenny 1 hour longer than Dennis to shuck a sack of oysters.
IF together they shuck a sack of oysters in 45 minutes, then how long would it take each one working alone?
:
change 45 min to .75 hrs
:
let t = time (in hrs) for Dennis to shuck a sack of oysters
then
(t+1) = time required by Kenny
:
Let the completed job = 1 (a sack of shucked oysters)
+ = 1
multiply by t(t+1), cancel the denominators
.75(t+1) + .75t = t(t+1)
.75t + .75 + .75t = t^2 + t
1.5t + .75 = t^2 + t
0 = t^2 + t - 1.5t - .75
a quadratic equation
t^2 - .5t - .75 = 0
using the quadratic formula; a=1; b=-.5; c=-.75, I got
t = -.65 (not a solution)
and
t = 1.15 hrs is Dennis's time alone (that's: 1 + .15(60) = 1 hr 9 min)
then
2.15 hrs is Kenny's time
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