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Two workers A and B together could finish a work in 8 days. They worked together for 6 days and A left the work.
The remaining work was completed by B alone in 6 days. How many days would each take to complete the work individually?
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Since two workers A and B together could finish the work in 8 days, and since they worked together for 6 days,
they just completed = of the work.
Hence, the remaining is of the work.
Since B completes it (completes this of the work) in 6 days, he can make the entire job in 6*4 = 24 days.
Now, the condition says that they complete the job in 8 days, working together.
During these 8 days, worker B makes of the job.
Hence, worker A alone makes of the job in 8 days.
Then, A makes the entire job in 12 days.
Solved. A needs 12 days to complete the job alone.
B needs 24 days to complete the job alone..
You do not need solve equations to get the answer.
All you need is to organize your thoughts LOGICALLY.
There is a wide variety of solved joint-work problems with detailed explanations in this site. See the lessons
- Using Fractions to solve word problems on joint work,
- Solving more complicated word problems on joint work,
- Selected joint-work word problems from the archive
Read them and get be trained in solving joint-work problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".