SOLUTION: 1. Find two integers whose product is 14 such that one of the integers is three less than five times the other integer. 2. The perimeter of a rectangle is 50 inches, and the ar

Question 1065940: 1. Find two integers whose product is 14 such that one of the integers is three less than five times the other integer.
2. The perimeter of a rectangle is 50 inches, and the area is 136 square inches. Find the length and width of the rectangle.
3. The combined area of a square and a rectangle is 124 square centimeters. The width of the rectangle is 4 centimeters more than the length of a side of the square, and the length of the rectangle is 2 centimeters more than its width. Find the dimensions of the square and the rectangle.
4. 9x3 + x2 + 7 from 5x3 − x − 8

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Doing #3 only

x, the side length of the square
x+4 is the width for the rectangle, and 2+(x+4) is the length of the rectangle.

Combined Area:

STEPS

This will mean that , side length of the square.

Evaluate the rectangle's x+4 and x+6.
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