SOLUTION: 2x^2 - x + 1/8 = 0
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Question 1064951: 2x^2 - x + 1/8 = 0
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
2x^2-x+(1/8)=0
16x^2-8x+1=0
(4x-1)^2=0
x=(1/4); this is a "bounce" at (1/4).
Check: (1/4)^2=(1/16)
*2=(1/8)
-1/4=-1/8
+1/8=0
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