SOLUTION: "where would you expect the vertex on the graph of y = (x

SOLUTION: "where would you expect the vertex on the graph of y = (x - 4)^2 + 5 to be?"

Question 1063: "where would you expect the vertex on the graph of y = (x - 4)^2 + 5 to be?"
Answer by usyim88hk(158) (Show Source): You can put this solution on YOUR website!
First, look at the general vertex form of parabola
:
y = (x-h)^2+k
:
where h is the location of the point on x-axis and k is the location of the point of the y-axis. So in your equation, y = (x-4)^2+5, the vertex is gonna be (4,5). Let me show u the graph...
:

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