SOLUTION: Find three consecutive odd positive integers such that 5 times the sum of all three is 60 more than the product of the first and second integers. The smallest odd integer is __

SOLUTION: Find three consecutive odd positive integers such that 5 times the sum of all three is 60 more than the product of the first and second integers. The smallest odd integer is ___

Question 1062176: Find three consecutive odd positive integers such that 5 times the sum of all three is 60 more than the product of the first and second integers.
The smallest odd integer is ___.
The next consecutive odd integer is ____.
The third consecutive odd integer is ____.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
n is a positive integer.

The numbers:

Equation for the description:

Simplify and solve for n;
use n to evaluate the three consecutive odd positive integers.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Find three consecutive odd positive integers such that 5 times the sum of all three is 60 more than the product of the first and second integers.
The smallest odd integer is ___.
The next consecutive odd integer is ____.
The third consecutive odd integer is ____.

With the smallest integer being S, the following equation is formed:
5(S + S + 2 + S + 4) = S(S + 2) + 60

Continue to solve for S, the smallest integer. Add 2 to S to get the middle integer, and then 4 to S to get the largest integer.
You will get 2 possible answers. Based on the given info. determine which is correct.
It's that simple.....nothing COMPLEX!!
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