Solve the equation by completing the square and applying the square root property. Write imaginary solutions in the form a+bį.
2a^2+4a+5=0
2a^2+4a=-5
((2a^2)/2)+(4a/2))=(-5/2)
(1/2)(2)^2) = 1
a^2+2a+1=-5/2+1
(a+1)^2=(-5/2)+(2/2)
(a+1)^2=-3/2
sqrt (a+1)^2=sqrt(-3/2)
a+1=+or- sqrt(3/2)į
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I must say, so far, I'm impressed
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