SOLUTION: z^2+2z-8 over z-5 multiplied by z^2-4z-5 over z^2+5z+4
Algebra.Com
Question 1057532: z^2+2z-8 over z-5 multiplied by z^2-4z-5 over z^2+5z+4
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
((z^2+2z-8) / (z-5)) * ((z^2-4z-5) / (z^2+5z+4)) =
:
((z+4)*(z-2)) / (z-5)) * ((z-5)*(z+1) / ((z+4)*(z+1))) =
:
*************
(z-2) / (z+4)
*************
:
RELATED QUESTIONS
z^2+5z+6 over z^2+10z+16 divided by z^2+3z over... (answered by mananth)
z-4 over z-2 equals 1 over... (answered by checkley77)
3z^-7+4z^-6+6z^-5+5z^-4+4z^-3+3z^-2+z^-1
(answered by Fombitz)
Simplify
z-1 over z + z+1 over... (answered by HasanSahin)
5(2-z)/4=-z (answered by jim_thompson5910)
2z+5(z-2)=-31 (answered by Anglophile)
z^2-64/z /... (answered by jim_thompson5910)
[(z^2 - 25) \ z] \ [(z - 5) \ (z -... (answered by jorel1380)
13 Z +4 -Z +5Z... (answered by Alan3354)