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A rectangle has one vertex on the line y = 8 – x (x > 0), another at the origin, one on the positive x-axis,
and one on the positive y-axis. Express the area A of the rectangle as a function of x.
Find the largest area A that can be enclosed by the rectangle.
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1. The area of a rectangle is A = x*(8-x), or A = -x^2 + 8x.
Simply because one dimension is x, while the other dimension is y = (8-x).
2. The maximum of the quadratic function A = -x^2 + 8x is at
x = = = 4.
Then x = 4, y = 8-x = 4 and A = 4*4 = 16 square units is the maximal area.
See the lessons
- HOW TO complete the square to find the minimum/maximum of a quadratic function
- Briefly on finding the minimum/maximum of a quadratic function
- HOW TO complete the square to find the vertex of a parabola
- Briefly on finding the vertex of a parabola
- A rectangle with a given perimeter which has the maximal area is a square
- A farmer planning to fence a rectangular garden to enclose the maximal area
- A farmer planning to fence a rectangular area along the river to enclose the maximal area
- A rancher planning to fence two adjacent rectangular corrals to enclose the maximal area
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Finding minimum/maximum of quadratic functions".