SOLUTION: A ball is thrown upward such that it's height (h) in t seconds is given by h=-16t^2 +8t +48 What is the maximum height reached by the ball?

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Question 1054211: A ball is thrown upward such that it's height (h) in t seconds is given by
h=-16t^2 +8t +48
What is the maximum height reached by the ball?
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Convert to vertex form by completing the square,



So the max height of occurs when .
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
A ball is thrown upward such that it's height (h) in t seconds is given by
h=-16t^2 +8t +48
What is the maximum height reached by the ball?
~~~~~~~~~~~~~~~~~~~~

Solution 

Apply completing the square to find the maximum of the given quadratic function.


 =  = .


The maximum is 49 feet.

See the lessons
    - HOW TO complete the square to find the minimum/maximum of a quadratic function
    - Briefly on finding the minimum/maximum of a quadratic function
    - HOW TO complete the square to find the vertex of a parabola
    - Briefly on finding the vertex of a parabola
in this site.

See also the lessons
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower


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