SOLUTION: A party of tourists booked a hotel for ₹1200. Three of the members failed to pay. Asa, result, each of the others had to pay ₹ 20 more. How many tourists were there in

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Question 1053932: A party of tourists booked a hotel for ₹1200. Three of the members failed to pay. Asa, result, each of the others had to pay ₹ 20 more. How many tourists were there in the party?
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.
A party of tourists booked a hotel for ₹1200. Three of the members failed to pay.
As a result, each of the others had to pay ₹ 20 more. How many tourists were there in the party?
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Solution 1 

(1)  n*p          = 1200,
(2)  (n-3)*(p+20) = 1200.

Express p =   from (1) and substitute it into (2) to get a single equation for n.


 = 1200.

Multiply both sides by n. You will get

(n-3)*(1200+20n) = 1200n.

Now simplify and solve for n.


Solution 2 

 -  = 20.

Multiply by n*(n-3) both sides. You will get

1200*n - 1200*(n-3) = 20*n*(n-3).

Simplify and solve for n.


Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
The cost is the same 1200, whatever that money unit.

How many tourists planned? v.
p for price for each of the planned v tourists.


Think very carefully about this before going further.



Planned situation is for an expected number of tourists and the expected price, for the given cost.

Actual situation did not change cost. Fewer tourists pay a higher price EACH and still together pay the same cost as planned.

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Now, solve the system and find v and p.
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