SOLUTION: Find two integers whose difference is 4 and whose square differ by 72

Algebra.Com
Question 1052973: Find two integers whose difference is 4 and whose square differ by 72
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
Answer. 11 and 7.

Solution 

 = 72  --->

(x-y)*(x+y) = 72.

But x-y = 4, according to the condition. Hence,

4*(x+y) = 72  --->

x + y =  = 18.

So, you have two equations:

x + y = 18,
x - y =  4.

Add them.

From this point, please complete the solution on your own.


Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

Find two integers whose difference is 4 and whose square differ by 72
Let larger and smaller integers be L and S, respectively

We then get: 

Simplify to get: 

You should be able to finish this! 

RELATED QUESTIONS


Find two numbers that differ by 6 and whose square roots differ by... (answered by solver91311)

Find two positive integers whose difference is 4 and whose product is... (answered by checkley77)

Find two numbers whose sum is 10 and whose squares differ by... (answered by checkley75)

Find two numbers whose sum is 72 and whose difference is 10. The two numbers... (answered by ikleyn,MathTherapy)

Find two integers, x and x + 1, whose squares differ by... (answered by MathLover1,bucky,jim_thompson5910)

find two integers whose difference is 23 and whose product is... (answered by ptaylor,stanbon)

find two integers whose difference is 23 and whose product is... (answered by Alan3354)

find two cosecutive odd integers whose sum is... (answered by Paul)

Find two consecutive integers whose product is... (answered by nerdybill)