SOLUTION: 1/x-4 +x/x-5 +1/x^2-9x+20=0 I have to solve for x I have the LCD to be(x-4)(x-5) I multiplied the numerator times the LCD and got (x-5)+x(x-4)+1=0. Next I got x-5+x^2-4x+1=0. I c

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Question 105218: 1/x-4 +x/x-5 +1/x^2-9x+20=0 I have to solve for x I have the LCD to be(x-4)(x-5) I multiplied the numerator times the LCD and got (x-5)+x(x-4)+1=0. Next I got x-5+x^2-4x+1=0. I combined my like terms and got -3x-4+x^=0. The x ^2 keeps throwing me off because I don't know what to do with it. Please show me what to do.
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
I'm going to start where you left off

Start with the given equation


Rearrange the terms


Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=1, b=-3, and c=-4




Negate -3 to get 3




Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or




However, since makes two terms of the original equation have a denominator of zero, our only true solution is



So our answer is


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