SOLUTION: y=(-1/2) x^2-3x+11
find the max or min value ofy and the value of x when it occurs. thanks.
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Question 1051593: y=(-1/2) x^2-3x+11
find the max or min value ofy and the value of x when it occurs. thanks.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y=(-1/2) x^2-3x+11
find the max or min value of y and the value of x when it occurs. thanks.
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Since the coefficient of x^2 is negative, y has a maximum value.
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Note:: Max occurs when x = -b/(2a) = 3/(2(-1/2)) = 3/-1 = -3
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The max value is f(-3) = (-1/2)(9)-3(-3)+11 = -4.5 + 20 = 15.5
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Cheers,
Stan H.
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