SOLUTION: I really need help for two questions.I tried doing these myself but I kept getting the wrong answers, and I'm not sure why. Please show your working so I can see how you get to the

Question 1051403: I really need help for two questions.I tried doing these myself but I kept getting the wrong answers, and I'm not sure why. Please show your working so I can see how you get to the answer.
1) What is the axis of symmetry for a parabola whose zeros are 2 and 5 (as in, the parabola crosses the x-axis at 2 and 5). What I got was 3 1/2, but somehow that's wrong.
2) What is the axis of symmetry for this quadratic function y = 3x^2 - 6x - 2. First I got 18, then 27, but both were marked wrong.
Please help, I really want to know where I went wrong.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
1)
parabola whose zeros are 2 and 5
y =a(x-2)(x-5)
y= a(x^2 - 7x + 10) a> 0
y= a(x-7/2)^2 + 49a/4 + 10)
x = 3.5 the axis of symmetry
2)
y = 3x^2 - 6x - 2
y = 3(x^2-2x +1) -3 - 2
y = 3(x-1)^2 - 5
axis of symmetry : x = 1
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Need to Know
the vertex form of a Parabola opening up(a>0) or down(a<0),
V(h,k) and x = h the axis of symmetry

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