SOLUTION: The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle? Let w represent the width of the rectan

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Question 1049378: The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?
Let w represent the width of the rectangle.
Found 2 solutions by ikleyn, hussamuddin:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?
Let w represent the width of the rectangle.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Let W represents the width of the rectangle.
Then its length is W+6.

Then the perimeter is 2W + 2(W+6).

Then for the perimeter you have an equation

2W + 2W + 12 = 68.

4W = 68 - 12,

4W = 56,

W =  = 14.

Answer.  The width is 14 ft, the length is 20 ft.

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Answer by hussamuddin(51)   (Show Source): You can put this solution on YOUR website!
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