SOLUTION: a toy rocket is launched from the top of a building 50 ft. tall at an initial velocity of 90 ft per second. Let t represent the amount of time elapsed after the launch. Solve.

Question 104934: a toy rocket is launched from the top of a building 50 ft. tall at an initial velocity of 90 ft per second. Let t represent the amount of time elapsed after the launch. Solve.

the answer is y= -16x2 + 90x + 50
How did the get the -16x squared??
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Well...
The general form of the equation that gives the height (h) of an object propelled upwards, as a function of time (t) is:
where: h is the height in feet, t is the time in seconds, g is the acceleration due to gravity (AMP Parsing Error of [g = 32 ft/sec^2)]: Invalid function ')': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. . , is the initial velocity of the object, and is the initial height of the object.
If you wanted to graph such an equation (it would be a parabola opening downward), it would be written as:

The x in your equation is a replacement variable for the time, t.
The first term is negative because of the downward effect of gravity on the object.
Just for fun, let's see what your equation would look like when graphed:

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