SOLUTION: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number?

Question 1045107: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number?
Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
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Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number?
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 = .


 = ,

n = 4n - 15,

15 = 3n,

n = 5.

The three consecutive numbers are  5,  6,  and 7.

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