SOLUTION: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

Question 1045089: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Let , , and be the 3 consecutive numbers.
= the product of the smaller two numbers
= the square of the largest number
= 19 less than the square of the largest number
The problem says that
.

Solving that equation:

The 3 consecutive numbers are
, , and .

Verification:
The product of the smaller two numbers is
19 less than the square of the largest number is

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