SOLUTION: I have worked out the quadratic equation for x= -3q^2+150q, where q is quantity. The question asks what is the quantity is if x = 150? So I'm basically being asked what is q? I g

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Question 1043584: I have worked out the quadratic equation for
x= -3q^2+150q, where q is quantity. The question asks what is the quantity is if x = 150? So I'm basically being asked what is q? I got:
q= 5(5 - radical 7) / 3 , q= 5(5 + radical 7) / 3
q=3.92375, q=12.74292.
But I don't know if that's the final answer to the question, or do I have to pick one of those two decimals?

Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Solved in
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https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1043586.html


Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
Apparently you made a mistake with the quadratic formula:

x = -3q2+150q 

substitute 150 for x

150 = -3q2+150q

Get 0 on the right side:

3q2-150q+150 = 0

To make it easier to solve, divide every 
term on both sides by 3 -- since you can!:

q2-50q+50 = 0

a=1, b=-50, c=50














 




 and 

 and 

Both answer are correct, so give them both.  You should
try to find out where you went wrong, so that you won't 
make the same mistake in other problems.

Edwin

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