Apparently you made a mistake with the quadratic formula: x = -3q2+150q substitute 150 for x 150 = -3q2+150q Get 0 on the right side: 3q2-150q+150 = 0 To make it easier to solve, divide every term on both sides by 3 -- since you can!: q2-50q+50 = 0 a=1, b=-50, c=50and and Both answer are correct, so give them both. You should try to find out where you went wrong, so that you won't make the same mistake in other problems. Edwin