Let y = the expression
Show that the denominator is never 0.
Show that it has derivative
Set that = 0 and show that it has relative
and absolute max at (-1,5/7) and an absolute
minimum at (1,-1).
Edwin
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website! The domain of the expression is the set of all real numbers. (The discriminant of the denominator implies that it itself is never zero.)
Let .
==> (after multiplication; note that the denominator is never zero)
==> <==> .
For x to have real values, the discriminant of this equation (with x as variable) must be greater than or equal to 0.
==> <==> , or
,
<==>
The inequality is only true when y ∈ [-1, 5/7].